Read the following information carefully to answer the questions that follow :
A sample poll of 200 votes revealed the following information concerning three candidates A, B and C of a certain party who were running for three different offices. 28 in favour of both A and B. 98 in favour of A or B but not C. 42 in favour of B but not A or C. 122 in favour of of B or C but not A. 64 in favour of C but not A or B. 14 in favour of A and C but not B.
Q. No. 1:
How many votes were in favour of all the three candidates ?
Here, g+d = 28......(i) a+d+b = 98 .......(ii) b = 42 .......(iii) b+c+e = 122 ......(iv) c = 64 ............(v) f = 14 ..........(vi) a+b+c+d+e+f+g = 200 .......(vii) Thus from all equations, a = 36, b = 42, c= 64, d= 20, e = 16, f = 14, g = 8. Clearly 8 votes were in favour of all the three candidates.
Q. No. 2:
How many votes were in favour of A irrespective of B or C ?
Here, g+d =
28......(i) a+d+b = 98 .......(ii) b = 42
.......(iii) b+c+e = 122 ......(iv) c = 64
............(v) f = 14 ..........(vi) a+b+c+d+e+f+g =
200 .......(vii) Thus from all equations, a = 36, b =
42, c= 64, d= 20, e = 16, f = 14, g = 8. Number of votes favouring A irrespective of B or C = 36+20 + 8+ 14 = 78
Q. No. 3:
How many votes were in favour of B irrespective of A or C?
Here, g+d =
28......(i) a+d+b = 98 .......(ii) b = 42
.......(iii) b+c+e = 122 ......(iv) c = 64
............(v) f = 14 ..........(vi) a+b+c+d+e+f+g =
200 .......(vii) Thus from all equations, a = 36, b =
42, c= 64, d= 20, e = 16, f = 14, g = 8. No. of votes favouring B irrespective of A or C = 42+20+16+8 = 86.
Q. No. 4:
How many votes were in favour of C irrespective of A or B ?
Here, g+d =
28......(i) a+d+b = 98 .......(ii) b = 42
.......(iii) b+c+e = 122 ......(iv) c = 64
............(v) f = 14 ..........(vi) a+b+c+d+e+f+g =
200 .......(vii) Thus from all equations, a = 36, b =
42, c= 64, d= 20, e = 16, f = 14, g = 8. No. of votes favouring C irrespective of B or C = 64+14+8+16 = 102.
Q. No. 5:
How many votes were in favour of A and B but not C ?
Here, g+d =
28......(i) a+d+b = 98 .......(ii) b = 42
.......(iii) b+c+e = 122 ......(iv) c = 64
............(v) f = 14 ..........(vi) a+b+c+d+e+f+g =
200 .......(vii) Thus from all equations, a = 36, b =
42, c= 64, d= 20, e = 16, f = 14, g = 8. The total number of voters favouring only one of the candidates => a+b+c = 36+42+64 = 142.
Q. No. 7:
How many votes were in favour of A and C but not B ?
Here, g+d =
28......(i) a+d+b = 98 .......(ii) b = 42
.......(iii) b+c+e = 122 ......(iv) c = 64
............(v) f = 14 ..........(vi) a+b+c+d+e+f+g =
200 .......(vii) Thus from all equations, a = 36, b =
42, c= 64, d= 20, e = 16, f = 14, g = 8. Number of votes favouring A and C but not B = f = 14.
Q. No. 8:
How many votes were in favour of B and C but not A?
Here, g+d =
28......(i) a+d+b = 98 .......(ii) b = 42
.......(iii) b+c+e = 122 ......(iv) c = 64
............(v) f = 14 ..........(vi) a+b+c+d+e+f+g =
200 .......(vii) Thus from all equations, a = 36, b =
42, c= 64, d= 20, e = 16, f = 14, g = 8. Number of votes favouring B and C but not A = e =16.
Study the following information and answer the questions that follow ::
The following are the result of the survey conducted on a small cross-section of students from Symbiosis Group of Institute to determine the readership of three magazines. This survey was conducted in Dec 2006. 1). Number of students who reads only Business India was 40. 2). 60 students read only Outlook. 3). 110 students read only India Today. 4). 30 students read all three magazines. 5). 20 read Business India and India today, but not Outlook. 6). 50 read Business India and Outlook, but not India Today. 7). 40 read Outlook and India Today, but not Business India.
When another survey was conducted in May 2007 with the same set of students, their tastes had changed and the findings were different. All of them read India Today. 120 read Outlook and no one read Business India. hence, in May 2007, how many students read only India today ?
Study the following information and answer the questions that follow ::
In a management institute, during the placement process of 100 students, 70 students got offers from the Finance area, 40 students got offers from Marketing area and 30 students got offer from HR area. Of these, 20 students received offers from the Finance and Marketing areas, 15 students got offers from the Marketing and HR areas and 10 students got offers from the HR and Finance areas.
Q. No. 1:
How many students received offers only from two areas ?
100=
70+40+30-20-15-10+x => x = 5.(Common to all
areas).
Percentage = (15/100) * 100 = 15%.
Q. No. 16:
Out of a total 85 children playing badminton or table tennis or both, total number of girls in the group is 70% of the total number of boys in the group. The number of boys playing only badminton is 50% of the number of boys and the total number of boys playing badminton is 60% of the total number of boys. The number of children playing only that table tennis is 40% of the total number of children and a total of 12 children play badminton and table tennis both. What is the number of girls playing only badminton ?
Answer: B Let the number of boys = x Then , x + 7x/10 = 85 => x = 50. Number of girls = 50 * 70/100 = 35.
Hence, the number of girls playing only badminton = 14.
The venn diagram given below shows the estimated readership of 3 daily
newspaper (X,Y and Z) in a city. The total readership and
advertising cost for each of these papers is as
below.
Newspaper
Readership(lakh)
Advertising cost (Rs
per cm2)
X
8.7
6000
Y
9.1
6500
Z
5.6
5000
The total population of the city
is estimated to be 14 million. The common readership (in lakh) is
indicated in the given venn diagram.
Q. No. 1:
The number of people (in lakh) who read at least one newspaper is :
Answer: C Total readership of X is 8.7 lakh. X+2.5 + 0.5 +1 = 8.7 => X = 4.7 lakh. Also, total readership of Y is 9.1 lakh => Y = 4.6 Similarly, Z = 2.6
Number of people who read at least one paper => 4.7+4.6+2.6+1+1.5+0.5+2.5 = 17.4
Q. No. 2:
The number of people (in lakh) who read only one newspaper is :
Answer: B Total readership of X is 8.7 lakh. X+2.5 + 0.5 +1 =
8.7 => X = 4.7 lakh. Also, total readership of Y
is 9.1 lakh => Y = 4.6 Similarly, Z =
2.6
Number of people who read at least one paper => 4.7+4.6+2.6 = 11.9.
Q. No. 18:
Of the 200 students at B-school. A majoring in one or more areas of subjects taught, 140 are majoring marketing and 150 are majoring in IT. If at least 30 of the students are not majoring in either marketing or IT, then the number of students majoring in both marketing and IT could be any number from